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f x = x 3 +1 . a. [2,3]b. [1,1]Find the slope of the curve using the definition of derivative at the given point and find the equation of the tangent line. ... is s(t) = (t3 – 12t2 + 36t 4) meters. Find all t values for which the velocity of the object is 0 m/sec, and give the position of the object on the s …

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(page 229, 63)( ) 2 sin2ts t e tπ−=Example 2:A particle moves according to a law of motion s = t3– 12t2+ 36t, t ≥ 0where t is measured in seconds and s in meters.(a) Find the velocity at time t.(b) What is the velocity after 3 sec?(c) When is the particle at rest?(d) When is the particle moving forward?(e) Find the total distance ...

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Oct 21, 2009· A particle moves according to a law of motion s = f(t) = t3 12t2 + 45t, t 0, where t is measured in seconds and s in feet... (a) When is the particle moving in the positive direction? (b) Find the total distance traveled during the first 7 s. (c) Find the acceleration at time t and after 4 s. (d) When is the particle speeding up?

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The position of a particle (in inches) moving along the xaxis after t seconds have elapsed is given by the following equation: s = f ( t ) = t 4 – 2 t 3 – 6 t 2 + 9 t (a) Calculate the velocity of the particle at time t .

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Obtenir le prixExl) The position of a particle moving along the xaxis is given by x(t) = t3 12t2 + 36t 20, for 0 stg 8. a) Find the velocity and acceleration of the particle. b) Find the open tintetvals when the particle is moving to the left. V '3 +6(0 3Cc)CL) c) Find the velocity of the particle when the acceleration is zero.

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Obtenir le prix12t2 +36t20 on The position function of a particle moving along the xaxis is given by x(t) = t3 (a) (b) (c) Find the velocity function and acceleration function of the particle. Find the open tintervals when the particle is moving to the left.

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At time t, the position of a body moving along the saxis is s = t^3 6t^2 + 9t m. A. Find the body's acceleration each time the velocity is zero. B. Find the body's speed each time the accelaration is zero. C. Find the total distance traveled by the body from t = 0 to t = 2.

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—x —8x—5 12t2 36tt3 24+10t2t2 5h3+4h27h where s is distance in metres and t is time in seconds. where h is height in metres and t is time in seconds. —15x+5 —8x—5 s=12t2 36tt h=24+10t2t where s is distance in metres and t is time in seconds.

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